#!/usr/bin/python
""" A python bubble-babble generator, inspired by
<http://woozle.org/t/bubblebabble.c>.
Here are the original Perl bubble-babble examples, for doctests:
>>> babble('432cc46b5c67c9adaabdcc6c69e23d6d'.decode('hex'))
'xibod-sycik-rilak-lydap-tipur-tifyk-sipuv-dazok-tixox'
>>> babble('5a1edbe07020525fd28cba1ea3b76694'.decode('hex'))
'xikic-vikyv-besed-begyh-zagim-sevic-vomer-lunon-gexex'
>>> babble('1c453603cdc914c1f2eeb1abddae2e03'.decode('hex'))
'xelag-hatyb-fafes-nehys-cysyv-vasop-rylop-vorab-fuxux'
>>> babble('df8ec33d78ae78280e10873f5e58d5ad'.decode('hex'))
'xulom-vebyf-tevyp-vevid-mufic-bucef-zylyh-mehyp-tuxax'
>>> babble('02b682a73739a9fb062370eaa8bcaec9'.decode('hex'))
'xebir-kybyp-latif-napoz-ricid-fusiv-popir-soras-nixyx'
"""
import itertools
consonants = "bcdfghklmnprstvz"
vowels = "aeiouy"
def maybe_ord(x):
"""If x is a string of length 1, return the ascii value. If it's a
longer string, return an iterator of values. Otherwise, coerce it
to an int()
>>> maybe_ord('A')
65
>>> tuple(maybe_ord('lol'))
(108, 111, 108)
>>> maybe_ord(242)
242
>>> maybe_ord(242.2222)
242
"""
try:
if len(x) is 1 and len(x[0]) is 1:
return ord(x)
else:
return itertools.imap(maybe_ord, x)
except:
return int(x)
def babble(digest, seed=1):
""" Compute bubble babble for input buffer.
>>> babble('')
'xexax'
>>> babble('1234567890')
'xesef-disof-gytuf-katof-movif-baxux'
>>> babble('Pineapple')
'xigak-nyryk-humil-bosek-sonax'
>>> babble('lol')
'xirak-zorex'
>>> import hashlib
>>> babble(hashlib.sha1('lol').digest())
'xibaf-nanob-fyzib-bikyh-davot-zotos-ryzah-decir-lucus-donoz-poxex'
>>> babble([70, 85, 129, 199])
'xicih-habes-laxex'
>>> babble(0)
'xebax'
"""
ret = 'x'
x = y = None
iters = [maybe_ord(digest)] * 2
for x,y in itertools.izip_longest(fillvalue=None, *iters):
ret += vowels[(((x >> 6) & 3) + seed) % 6]
ret += consonants[(x >> 2) & 15]
ret += vowels[((x & 3) + (seed / 6)) % 6]
if y is not None:
seed = ((seed * 5) + (x * 7) + y) % 36
ret += consonants[(y >> 4) & 15]
ret += '-'
ret += consonants[y & 15]
if y is not None or x is None:
ret += vowels[seed % 6] + 'x' + vowels[seed / 6]
return ret + 'x'
if __name__ == '__main__':
import doctest
doctest.testmod()
