# (IMHO) the simplest approach: def sortedDictValues1(adict): items = adict.items() items.sort() return [value for key, value in items] # an alternative implementation, which # happens to run a bit faster for large # dictionaries on my machine: def sortedDictValues2(adict): keys = adict.keys() keys.sort() return [dict[key] for key in keys] # a further slight speed-up on my box # is to map a bound-method: def sortedDictValues3(adict): keys = adict.keys() keys.sort() return map(adict.get, keys)