def first(seq, pred=None):
"""Return the first item in seq for which the predicate is true.
If the predicate is None, return the first item regardless of value.
If no items satisfy the predicate, return None.
"""
if pred is None:
pred = lambda x: True
for item in seq:
if pred(item):
return item
return None
def last(seq, pred=None):
"""Return the last item in seq for which the predicate is true.
If the predicate is None, return the last item regardless of value.
If no items satisfy the predicate, return None.
"""
if pred is None:
pred = lambda x: True
for item in reversed(seq):
if pred(item):
return item
return None
# Just get the first item :)
# >>> seq = 'abc'
# >>> first(seq)
# 'a'
# Get the first item greater than 10
# >>> seq = [1, 2, 4, 12, 13, 15, 17]
# >>> first(seq, lambda x: x > 10)
# 12
# Get the last non-None/False/empty item
# >>> seq = ["one", "two", "three", "", None]
# >>> last(seq, bool)
# 'three'
