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A Loopless FizzBuzz

Python, 5 lines
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n=map(str, range(101))
n[::3]=['Fizz']*34
n[::5]=['Buzz']*21
n[::15]=['FizzBuzz']*7
print '\n'.join(n[1:])

References :
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3 comments

Louis RIVIERE (author) 12 years, 10 months ago  # | flag

Alernative :

n=map(str, range(101))
n[::3]=['Fizz']*34
n[::5]=map(lambda a:'FizzBuzz' if a=='Fizz' else 'Buzz', n[::5])
print '\n'.join(n[1:])
Louis RIVIERE (author) 12 years, 10 months ago  # | flag

Alternative :

n=map(str, range(101))
n[::5]=['']*21
n[::3]=['Fizz']*34
n[::5]=map(lambda a:a+'Buzz', n[::5])
print '\n'.join(n[1:])
userend 10 years, 1 month ago  # | flag

That is shorter than the version I came up with.

Created by Louis RIVIERE on Tue, 13 Jan 2009 (MIT)
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