Popular recipes tagged "reduce" but not "lambda"http://code.activestate.com/recipes/tags/reduce-lambda/2013-01-05T05:49:27-08:00ActiveState Code RecipesTraverse dotted attribute of an object using built-in function reduce (Python) 2013-01-05T05:49:27-08:00Chaobin Tang (唐超斌)http://code.activestate.com/recipes/users/4174076/http://code.activestate.com/recipes/578398-traverse-dotted-attribute-of-an-object-using-built/ <p style="color: grey"> Python recipe 578398 by <a href="/recipes/users/4174076/">Chaobin Tang (唐超斌)</a> (<a href="/recipes/tags/attributes/">attributes</a>, <a href="/recipes/tags/bif/">bif</a>, <a href="/recipes/tags/recursive/">recursive</a>, <a href="/recipes/tags/reduce/">reduce</a>). </p> <p>Making good use of reduce() to traverse dotted attribute of an object.</p> Sharing-aware tree transformations (Python) 2012-05-07T08:20:58-07:00Sander Evershttp://code.activestate.com/recipes/users/4173111/http://code.activestate.com/recipes/578117-sharing-aware-tree-transformations/ <p style="color: grey"> Python recipe 578117 by <a href="/recipes/users/4173111/">Sander Evers</a> (<a href="/recipes/tags/fold/">fold</a>, <a href="/recipes/tags/reduce/">reduce</a>, <a href="/recipes/tags/sharing/">sharing</a>, <a href="/recipes/tags/tree/">tree</a>, <a href="/recipes/tags/yaml/">yaml</a>). Revision 2. </p> <p>The function <code>foldsh</code> in this recipe is a general purpose tool for transforming tree-like recursive data structures while keeping track of shared subtrees.</p> <pre class="prettyprint"><code># By default, a branch is encoded as a list of subtrees; each subtree can be a # branch or a leaf (=anything non-iterable). Subtrees can be shared: &gt;&gt;&gt; subtree = [42,44] &gt;&gt;&gt; tree = [subtree,[subtree]] # We can apply a function to all leaves: &gt;&gt;&gt; foldsh(tree, leaf= lambda x: x+1) [[43, 45], [[43, 45]]] # Or apply a function to the branches: &gt;&gt;&gt; foldsh(tree, branch= lambda t,c: list(reversed(c))) [[[44, 42]], [44, 42]] # The sharing is preserved: &gt;&gt;&gt; _[0][0] is _[1] True # Summing up the leaves without double counting of shared subtrees: &gt;&gt;&gt; foldsh(tree, branch= lambda t,c: sum(c), shared= lambda x: 0) 86 </code></pre> <p>In particular, it is useful for transforming YAML documents. An example of this is given below.</p> Cycle-aware tree transformations (Python) 2012-06-20T08:09:13-07:00Sander Evershttp://code.activestate.com/recipes/users/4173111/http://code.activestate.com/recipes/578118-cycle-aware-tree-transformations/ <p style="color: grey"> Python recipe 578118 by <a href="/recipes/users/4173111/">Sander Evers</a> (<a href="/recipes/tags/cyclic/">cyclic</a>, <a href="/recipes/tags/fold/">fold</a>, <a href="/recipes/tags/reduce/">reduce</a>, <a href="/recipes/tags/yaml/">yaml</a>). </p> <p>A variation on <a href="http://code.activestate.com/recipes/578117/">Recipe 578117</a> that can deal with cycles. A cycle means that a tree has itself as a subtree somewhere. A fold over such a data structure has a chicken-and-egg-problem: it needs its own result in order to construct its own result. To solve this problem, we let <code>branch</code> construct a <em>part</em> of its result before going into recursion. After the recursion, <code>branch</code> gets a chance to complete its result using its children's results. Python's support for coroutines (using <code>yield</code>) provides a nice way to define such a two-stage <code>branch</code> function.</p> Finding the GCD of a list of numbers (a.k.a. Reducing numbers in a list) (Python) 2010-07-06T18:52:55-07:00Stephen Akikihttp://code.activestate.com/recipes/users/4172143/http://code.activestate.com/recipes/577282-finding-the-gcd-of-a-list-of-numbers-aka-reducing-/ <p style="color: grey"> Python recipe 577282 by <a href="/recipes/users/4172143/">Stephen Akiki</a> (<a href="/recipes/tags/common/">common</a>, <a href="/recipes/tags/denominator/">denominator</a>, <a href="/recipes/tags/gcd/">gcd</a>, <a href="/recipes/tags/greatest/">greatest</a>, <a href="/recipes/tags/lisst/">lisst</a>, <a href="/recipes/tags/reduce/">reduce</a>). </p> <p><a href="http://akiscode.com/articles/gcd_of_a_list.shtml" rel="nofollow">http://akiscode.com/articles/gcd_of_a_list.shtml</a></p> <p>This python code snippet allows you to find the GCD of a list of numbers, after this it is a simple matter of diving all the numbers in the list by the GCD to reduce it.</p> <p>Why this works...</p> <p>The GCD of a list of numbers [a, b, c] is GCD(GCD(a, b), c). The reduce function does exactly this and thus gives you the GCD of all the numbers in the list.</p>