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def inversion(permList):
    """
    Description - This function returns the number of inversions in a
                  permutation.
    Preconditions - The parameter permList is a list of unique positve numbers.

    Postconditions - The number of inversions in permList has been returned.

    Input - permList : list
    Output - numInversions : int
    """
    if len(permList)==1:
        return 0
    else:
        numInversion=len(permList)-permList.index(max(permList))-1
        permList.remove(max(permList))
        return numInversion+inversion(permList)

Diff to Previous Revision

--- revision 1 2015-05-05 00:40:12
+++ revision 2 2016-02-21 06:00:46
@@ -1,45 +1,17 @@
-def I(tupPerm):
-    tmpList=[]
-    for k in tupPerm:
-        tmpL=list(tupPerm)
-        kIndex=tmpL.index(k)
-        copyTup=[x for x in tmpL]
-        copyTup2=copyTup[(kIndex+1):]
-        ctInversionsForKList=[]
-        for x in copyTup2:
-            if x<k:
-                ctInversionsForKList.append(1)
-        tmpList.append(sum(ctInversionsForKList))
-    return sum(tmpList)
+def inversion(permList):
+    """
+    Description - This function returns the number of inversions in a
+                  permutation.
+    Preconditions - The parameter permList is a list of unique positve numbers.
 
-def p(n,r):
-    from itertools import permutations
-    tmp=permutations([x for x in range(1,n+1)],r)
-    tupPermList=list(tmp)
-    return tupPermList
+    Postconditions - The number of inversions in permList has been returned.
 
-def convertStdForm(tupPerm):
-    tmpS=''
-    for u in tupPerm:
-        tmpS+=str(u)
-    return eval(tmpS)     
-
-ans=""
-from itertools import permutations
-while ans!="N":
-    print()
-    n=eval(input("Please enter the int n for which permutations will be taken from: "))
-    print()
-    tupPerms=p(n,n)
-    permsWithLessThan3Inversions=[]
-    for tup in tupPerms:
-        if I(tup)<3:
-            permsWithLessThan3Inversions.append(tup)   
-    stdPermForm=[]
-    for tup in permsWithLessThan3Inversions:
-        stdPermForm.append(convertStdForm(tup))
-    print("The number of permutations of length ",n," from the set ",[x for x in range(1,n+1)]," that have inversion numbers no greater than 2 are given as follows: ")
-    print()
-    for x in stdPermForm:
-        print(x,end=", ")
-    print()
+    Input - permList : list
+    Output - numInversions : int
+    """
+    if len(permList)==1:
+        return 0
+    else:
+        numInversion=len(permList)-permList.index(max(permList))-1
+        permList.remove(max(permList))
+        return numInversion+inversion(permList)

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