This program will take input from the user and either check if a number is a perfect square or square a number, depending on user's choice.
Python, 42 lines
Download
Copy to clipboard1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 | __author__ = 'Ethan D. Hann'
import math
print("Is your number a perfect square?! Find out now!")
print("Or you can square a number!")
#Setting up while loop with loop-controlled variable
x = 1
while x > 0:
#Get input from user
op = input("q -> quit program \n" \
"c -> checks a number \n" \
"s -> squares a number \n")
#Check if input is c, s, or q
if op[0] is "c":
#If c, take the square root of the number and round it to the largest integer value less than or equal to x: math.floor(x)
num = input("Enter a whole number (q -> quit): ")
sNum = math.floor(math.sqrt(int(num)))
numSquared = sNum * sNum
#If, else statement to determine if numSquared is equal to the input.
if numSquared == int(num):
print(num, "IS a perfect square! \n"\
"√("+ num + ") =", math.sqrt(int(num)))
else:
print(num, "is NOT a perfect square! \n" \
"√("+ num + ") =", math.sqrt(int(num)))
#If s, simply square user's input
if op[0] is "s":
num = int(input("Enter a number to square (q -> quit): "))
numSquared = num ** 2
print(num, "squared is", numSquared)
#If q, quit program with goodbye message
else:
if op[0] is 'q':
x -= 1
print("Goodbye!")
else:
print("Must enter either c, s, or q")
|
Would it not make more sense in using following code to determine if the input number was a perfect square?:
if math.sqrt(num).is_integer(): print "Perfect square" else: print "Not a perfect square"