Remove Duplicacy from a Python List (Python recipe) by Bibha Tripathi

ActiveState Code (http://code.activestate.com/recipes/440509/)

This could be much shorter, and really doesn't need to be a function:

from sets import Set
new_list = list(Set(old_list))

This won't preserve the order of the original list, of course.

Thanks Nick. But is the list object callable?

I get the following when I run the above:

>>> new_list = list(Set(old_list))
Traceback (most recent call last):
  File "", line 1, in ?
TypeError: 'list' object is not callable

Don't redefine the list() built-in. >>> from sets import Set

>>> old_list = [1,2,3,3,4,4,4,5]



>>> new_list = list(Set(old_list))



>>> list = []



>>> new_list = list(Set(old_list))

Traceback (most recent call last):

File "", line 1, in ?

TypeError: 'list' object is not callable

And as of 2.4... Even simpler, and faster, as of Python 2.4 with the C implementation of set data type in the core:

->> L = [1,1,1,2,3,1,5,6,7] ->> list(set(L)) [1, 2, 3, 5, 6, 7]

Mike Watkins: oops, left result out.

->> L = [1,1,1,2,3,1,5,6,7]

->> list(set(L))

[1, 2, 3, 5, 6, 7]

For versions later 2.3. a = [1, 2, 2, 3, 4, 4, 5] b = {} for i in a: b[i] = 0 a = b.keys()

a = [1, 2, 2, 3, 4, 4, 5]



b = {}



for i in a: b[i] = 0



a = b.keys()