A (mostly) one-liner that cuts an iterable into X sized chunks...
Python, 10 lines
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Copy to clipboard1 2 3 4 5 6 7 8 9 10 | >>> a,bite = "supercalifragalisticexpialidocious",3
>>> [(a[d:d+bite]) for d in range(len(a)-bite) if d%bite==0]
[('s', 'u', 'p'), ('e', 'r', 'c'), ('a', 'l', 'i'), ('f', 'r', 'a'), ('g', 'a', 'l'), ('i', 's', 't'), ('i', 'c', 'e'), ('x', 'p', 'i'), ('a', 'l', 'i'), ('d', 'o', 'c'), ('i', 'o', 'u')]
>>> # or on a list
>>> b =['sup', 'erc', 'ali', 'fra', 'gal', 'ist', 'ice', 'xpi', 'ali', 'doc', 'iou']
>>>
>>> [(b[d:d+bite]) for d in range(len(b)-bite) if d%bite==0]
[['sup', 'erc', 'ali'], ['fra', 'gal', 'ist'], ['ice', 'xpi', 'ali']]
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WARNING: This code truncates the data if the source data is not evenly divisible by the chunksize...
In my case, I knew the data was evenly divisible beforehand, so this was no problem...
If there is an easier way of doing this, please post it.
Tags: shortcuts
Also, you can do this with:
So that your code works like:
However, Guido views this as an abuse of the argument parsing machinery.
This might work better. [a[x:x+bite] for x in range(0,len(a),bite)]
... but it does not cut off the tail if len % bite != 0. If you need it, use