Dictionaries can't be sorted -- a mapping has no ordering! -- so, when you feel the need to sort one, you no doubt want to sort its keys (in a separate list). Sorting (key,value) pairs (items) is simplest, but not fastest.
Python, 20 lines
The concept of 'sort' applies only to a collection which has _order_ -- a sequence; a mapping (e.g. a dictionary) has NO order, thus it cannot be sorted. Still, its keys can be extracted as a list, which can then be sorted. The example functions return the values in order of sorted key, which just happens to be the single most frequent actual need corresponding to user questions such as "how do I sort a dictionary":-)
The implementation choices are interesting. Since we are sorting key-value pairs by the key field, then returning the list of value fields, it seems clearest (conceptually simplest) to architect the solution as in the first example: .items, .sort, then a list comprehension to pick the value fields.
However (at least on my machine) this turns out not to be fastest: extracting just the keys, sorting them, then accessing the dictionary for each key in the resulting list comprehension, as in the second example, appears to be speedier.
Furthermore, it is subject to a further, obvious optimization: from the dictionary we can extract just once the bound-method adict.get, which will map each key to the corresponding value, then use builtin function map to build the list obtained by applying this callable to each item in the sorted list of keys. This does indeed provide a further speed-up (again, on my machine).
Simplicity is a great virtue, but the second and third examples aren't really more complicated (or complex) than the first -- just, perhaps, a little bit subtler. They're probably worth using to 'sort' any dictionary, even though their performance advantages are really only measurable for large ones -- because uniformity of idiom is also an important programming virtue!